-0.0444x^2+0.3333x=0

Solution for -0.0444x^2+0.3333x=0 equation:

-0.0444x^2+0.3333x=0

a = -0.0444; b = 0.3333; c = 0;
Δ = b2-4ac
Δ = 0.33332-4·(-0.0444)·0
Δ = 0.11108889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.3333)-\sqrt{0.11108889}}{2*-0.0444}=\frac{-0.3333-\sqrt{0.11108889}}{-0.0888}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.3333)+\sqrt{0.11108889}}{2*-0.0444}=\frac{-0.3333+\sqrt{0.11108889}}{-0.0888}
$